Optimal. Leaf size=134 \[ -\frac{a^2 \cosh (c+d x)}{d^2}+\frac{a^2 x \sinh (c+d x)}{d}+\frac{4 a b \sinh (c+d x)}{d^3}-\frac{4 a b x \cosh (c+d x)}{d^2}+\frac{2 a b x^2 \sinh (c+d x)}{d}-\frac{3 b^2 x^2 \cosh (c+d x)}{d^2}+\frac{6 b^2 x \sinh (c+d x)}{d^3}-\frac{6 b^2 \cosh (c+d x)}{d^4}+\frac{b^2 x^3 \sinh (c+d x)}{d} \]
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Rubi [A] time = 0.214288, antiderivative size = 134, normalized size of antiderivative = 1., number of steps used = 11, number of rules used = 4, integrand size = 15, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.267, Rules used = {6742, 3296, 2638, 2637} \[ -\frac{a^2 \cosh (c+d x)}{d^2}+\frac{a^2 x \sinh (c+d x)}{d}+\frac{4 a b \sinh (c+d x)}{d^3}-\frac{4 a b x \cosh (c+d x)}{d^2}+\frac{2 a b x^2 \sinh (c+d x)}{d}-\frac{3 b^2 x^2 \cosh (c+d x)}{d^2}+\frac{6 b^2 x \sinh (c+d x)}{d^3}-\frac{6 b^2 \cosh (c+d x)}{d^4}+\frac{b^2 x^3 \sinh (c+d x)}{d} \]
Antiderivative was successfully verified.
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Rule 6742
Rule 3296
Rule 2638
Rule 2637
Rubi steps
\begin{align*} \int x (a+b x)^2 \cosh (c+d x) \, dx &=\int \left (a^2 x \cosh (c+d x)+2 a b x^2 \cosh (c+d x)+b^2 x^3 \cosh (c+d x)\right ) \, dx\\ &=a^2 \int x \cosh (c+d x) \, dx+(2 a b) \int x^2 \cosh (c+d x) \, dx+b^2 \int x^3 \cosh (c+d x) \, dx\\ &=\frac{a^2 x \sinh (c+d x)}{d}+\frac{2 a b x^2 \sinh (c+d x)}{d}+\frac{b^2 x^3 \sinh (c+d x)}{d}-\frac{a^2 \int \sinh (c+d x) \, dx}{d}-\frac{(4 a b) \int x \sinh (c+d x) \, dx}{d}-\frac{\left (3 b^2\right ) \int x^2 \sinh (c+d x) \, dx}{d}\\ &=-\frac{a^2 \cosh (c+d x)}{d^2}-\frac{4 a b x \cosh (c+d x)}{d^2}-\frac{3 b^2 x^2 \cosh (c+d x)}{d^2}+\frac{a^2 x \sinh (c+d x)}{d}+\frac{2 a b x^2 \sinh (c+d x)}{d}+\frac{b^2 x^3 \sinh (c+d x)}{d}+\frac{(4 a b) \int \cosh (c+d x) \, dx}{d^2}+\frac{\left (6 b^2\right ) \int x \cosh (c+d x) \, dx}{d^2}\\ &=-\frac{a^2 \cosh (c+d x)}{d^2}-\frac{4 a b x \cosh (c+d x)}{d^2}-\frac{3 b^2 x^2 \cosh (c+d x)}{d^2}+\frac{4 a b \sinh (c+d x)}{d^3}+\frac{6 b^2 x \sinh (c+d x)}{d^3}+\frac{a^2 x \sinh (c+d x)}{d}+\frac{2 a b x^2 \sinh (c+d x)}{d}+\frac{b^2 x^3 \sinh (c+d x)}{d}-\frac{\left (6 b^2\right ) \int \sinh (c+d x) \, dx}{d^3}\\ &=-\frac{6 b^2 \cosh (c+d x)}{d^4}-\frac{a^2 \cosh (c+d x)}{d^2}-\frac{4 a b x \cosh (c+d x)}{d^2}-\frac{3 b^2 x^2 \cosh (c+d x)}{d^2}+\frac{4 a b \sinh (c+d x)}{d^3}+\frac{6 b^2 x \sinh (c+d x)}{d^3}+\frac{a^2 x \sinh (c+d x)}{d}+\frac{2 a b x^2 \sinh (c+d x)}{d}+\frac{b^2 x^3 \sinh (c+d x)}{d}\\ \end{align*}
Mathematica [A] time = 0.188351, size = 87, normalized size = 0.65 \[ \frac{d \left (a^2 d^2 x+2 a b \left (d^2 x^2+2\right )+b^2 x \left (d^2 x^2+6\right )\right ) \sinh (c+d x)-\left (a^2 d^2+4 a b d^2 x+3 b^2 \left (d^2 x^2+2\right )\right ) \cosh (c+d x)}{d^4} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.01, size = 283, normalized size = 2.1 \begin{align*}{\frac{1}{{d}^{2}} \left ({\frac{{b}^{2} \left ( \left ( dx+c \right ) ^{3}\sinh \left ( dx+c \right ) -3\, \left ( dx+c \right ) ^{2}\cosh \left ( dx+c \right ) +6\, \left ( dx+c \right ) \sinh \left ( dx+c \right ) -6\,\cosh \left ( dx+c \right ) \right ) }{{d}^{2}}}-3\,{\frac{c{b}^{2} \left ( \left ( dx+c \right ) ^{2}\sinh \left ( dx+c \right ) -2\, \left ( dx+c \right ) \cosh \left ( dx+c \right ) +2\,\sinh \left ( dx+c \right ) \right ) }{{d}^{2}}}+2\,{\frac{ab \left ( \left ( dx+c \right ) ^{2}\sinh \left ( dx+c \right ) -2\, \left ( dx+c \right ) \cosh \left ( dx+c \right ) +2\,\sinh \left ( dx+c \right ) \right ) }{d}}+3\,{\frac{{c}^{2}{b}^{2} \left ( \left ( dx+c \right ) \sinh \left ( dx+c \right ) -\cosh \left ( dx+c \right ) \right ) }{{d}^{2}}}-4\,{\frac{cba \left ( \left ( dx+c \right ) \sinh \left ( dx+c \right ) -\cosh \left ( dx+c \right ) \right ) }{d}}+{a}^{2} \left ( \left ( dx+c \right ) \sinh \left ( dx+c \right ) -\cosh \left ( dx+c \right ) \right ) -{\frac{{b}^{2}{c}^{3}\sinh \left ( dx+c \right ) }{{d}^{2}}}+2\,{\frac{b{c}^{2}a\sinh \left ( dx+c \right ) }{d}}-c{a}^{2}\sinh \left ( dx+c \right ) \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 1.17618, size = 371, normalized size = 2.77 \begin{align*} -\frac{1}{24} \, d{\left (\frac{6 \,{\left (d^{2} x^{2} e^{c} - 2 \, d x e^{c} + 2 \, e^{c}\right )} a^{2} e^{\left (d x\right )}}{d^{3}} + \frac{6 \,{\left (d^{2} x^{2} + 2 \, d x + 2\right )} a^{2} e^{\left (-d x - c\right )}}{d^{3}} + \frac{8 \,{\left (d^{3} x^{3} e^{c} - 3 \, d^{2} x^{2} e^{c} + 6 \, d x e^{c} - 6 \, e^{c}\right )} a b e^{\left (d x\right )}}{d^{4}} + \frac{8 \,{\left (d^{3} x^{3} + 3 \, d^{2} x^{2} + 6 \, d x + 6\right )} a b e^{\left (-d x - c\right )}}{d^{4}} + \frac{3 \,{\left (d^{4} x^{4} e^{c} - 4 \, d^{3} x^{3} e^{c} + 12 \, d^{2} x^{2} e^{c} - 24 \, d x e^{c} + 24 \, e^{c}\right )} b^{2} e^{\left (d x\right )}}{d^{5}} + \frac{3 \,{\left (d^{4} x^{4} + 4 \, d^{3} x^{3} + 12 \, d^{2} x^{2} + 24 \, d x + 24\right )} b^{2} e^{\left (-d x - c\right )}}{d^{5}}\right )} + \frac{1}{12} \,{\left (3 \, b^{2} x^{4} + 8 \, a b x^{3} + 6 \, a^{2} x^{2}\right )} \cosh \left (d x + c\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.00752, size = 203, normalized size = 1.51 \begin{align*} -\frac{{\left (3 \, b^{2} d^{2} x^{2} + 4 \, a b d^{2} x + a^{2} d^{2} + 6 \, b^{2}\right )} \cosh \left (d x + c\right ) -{\left (b^{2} d^{3} x^{3} + 2 \, a b d^{3} x^{2} + 4 \, a b d +{\left (a^{2} d^{3} + 6 \, b^{2} d\right )} x\right )} \sinh \left (d x + c\right )}{d^{4}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 2.11423, size = 172, normalized size = 1.28 \begin{align*} \begin{cases} \frac{a^{2} x \sinh{\left (c + d x \right )}}{d} - \frac{a^{2} \cosh{\left (c + d x \right )}}{d^{2}} + \frac{2 a b x^{2} \sinh{\left (c + d x \right )}}{d} - \frac{4 a b x \cosh{\left (c + d x \right )}}{d^{2}} + \frac{4 a b \sinh{\left (c + d x \right )}}{d^{3}} + \frac{b^{2} x^{3} \sinh{\left (c + d x \right )}}{d} - \frac{3 b^{2} x^{2} \cosh{\left (c + d x \right )}}{d^{2}} + \frac{6 b^{2} x \sinh{\left (c + d x \right )}}{d^{3}} - \frac{6 b^{2} \cosh{\left (c + d x \right )}}{d^{4}} & \text{for}\: d \neq 0 \\\left (\frac{a^{2} x^{2}}{2} + \frac{2 a b x^{3}}{3} + \frac{b^{2} x^{4}}{4}\right ) \cosh{\left (c \right )} & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.14316, size = 231, normalized size = 1.72 \begin{align*} \frac{{\left (b^{2} d^{3} x^{3} + 2 \, a b d^{3} x^{2} + a^{2} d^{3} x - 3 \, b^{2} d^{2} x^{2} - 4 \, a b d^{2} x - a^{2} d^{2} + 6 \, b^{2} d x + 4 \, a b d - 6 \, b^{2}\right )} e^{\left (d x + c\right )}}{2 \, d^{4}} - \frac{{\left (b^{2} d^{3} x^{3} + 2 \, a b d^{3} x^{2} + a^{2} d^{3} x + 3 \, b^{2} d^{2} x^{2} + 4 \, a b d^{2} x + a^{2} d^{2} + 6 \, b^{2} d x + 4 \, a b d + 6 \, b^{2}\right )} e^{\left (-d x - c\right )}}{2 \, d^{4}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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